Advertisements
Advertisements
प्रश्न
If `x = 2` is a root of the polynomial `f(x) = 2x2 – 3x + 7a` find the value of a.
Advertisements
उत्तर
We have f(x) = 2x2 – 3x + 7a
put `x=2⇒ f(2)=2(2)^2-3(2)+7a`
`=2xx4-3xx2+7a=8-6+7`
`=2+7a`
given `x=2` is a root of `f(x)=2x^2-3x=7a`
`⇒f(2)=0`
`∴2+7a=0`
`⇒7a=-2⇒ a=-2/7`
APPEARS IN
संबंधित प्रश्न
Identify polynomials in the following:
`h(x)=x^4-x^(3/2)+x-1`
If f(x) = 2x2 - 13x2 + 17x + 12 find f(-3).
If x − 2 is a factor of the following two polynomials, find the values of a in each case x5 − 3x4 − ax3 + 3ax2 + 2ax + 4.
What must be subtracted from x3 − 6x2 − 15x + 80 so that the result is exactly divisible by x2 + x − 12?
x3 − 2x2 − x + 2
x4 − 2x3 − 7x2 + 8x + 12
If x − 3 is a factor of x2 − ax − 15, then a =
If x2 − 1 is a factor of ax4 + bx3 + cx2 + dx + e, then
Factorise the following:
6x2 + 16xy + 8y2
If x + 2a is a factor of x5 – 4a2x3 + 2x + 2a + 3, find a.
