Advertisements
Advertisements
प्रश्न
Factorise.
63a2 − 112b2
योग
Advertisements
उत्तर
63a2 − 112b2
On writing it as follows:
= 7(9a2 − 16b2)
= 7 [(3a)2 − (4b)2]
Using the identity a2 − b2 = (a − b) (a + b)
= 7(3a − 4b) (3a + 4b)
= a2 − b2
= (a − b) (a + b)
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 12: Factorisation - EXERCISE 12.2 [पृष्ठ १५१]
APPEARS IN
संबंधित प्रश्न
Factorise the following expression.
a2 + 8a + 16
Factorise the following expression.
p2 − 10p + 25
Factorise the following expression.
49y2 + 84yz + 36z2
Factorise.
(l + m)2 − (l − m)2
Factorise.
9x2y2 − 16
Factorise the expression.
ax2 + bx
Factorise the expression.
5y2 − 20y − 8z + 2yz
Factorise.
x4 − (x − z)4
Factorise 49p2 – 36
Factorise a2 – 2ab + b2 – c2.
