Advertisements
Advertisements
प्रश्न
Factorise.
x4 − (y + z)4
योग
Advertisements
उत्तर
x4 − (y + z)4
= (x2)2 − [(y + z)2]2
Using the identity a2 − b2 = (a − b) (a + b)
= [x2 − (y + z)2] [x2 + (y + z)2]
Again, using a2 − b2 = (a − b) (a + b)
= [x − (y + z)] [x + (y + z)] [x2 + (y + z)2]
= (x − y + z) (x + y + z) [x2 + (y + z)2]
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 12: Factorisation - EXERCISE 12.2 [पृष्ठ १५२]
APPEARS IN
संबंधित प्रश्न
Factorise the following expression.
49y2 + 84yz + 36z2
Factorise the following expression.
121b2 − 88bc + 16c2
Factorise.
49x2 − 36
Factorise.
(x2 − 2xy + y2) − z2
Factorise.
25a2 − 4b2 + 28bc − 49c2
Factorise the expression.
5y2 − 20y − 8z + 2yz
Factorise 49p2 – 36
Factorise m4 – 256
Factorise the following expression:
ab – ac – mb + mc
Factorise the following by taking out the common factor
3y3 – 48y
