Advertisements
Advertisements
प्रश्न
Explain optical isomerism in 2-chlorobutane.
Advertisements
उत्तर
- The stereoisomerism in which the isomers have different spatial arrangements of groups/atoms around a chiral atom is called optical isomerism.
- 2-chlorobutane has one chiral carbon atom. The spatial arrangement of the four different groups around the chiral atom is different.
- Structure of 2-chlorobutane and its mirror image can be represented as:
- 2-Chlorobutane cannot superimpose perfectly on its mirror image as shown in the figure. Hence, 2-chlorobutane exhibits optical isomerism.
APPEARS IN
संबंधित प्रश्न
Identify the chiral molecule from the following.
Identify chiral molecule/s from the following.
For the isomeric dihalobenzenes, melting point of __________
Optical activity of a molecule is associated with _______________
Explain optical activity of 2-chlorobutane.
Identify the INCORRECT statement.
Calcite crystals used in Nicol's prism are formed of ______.
While assigning R, S configuration, the correct order of priority of groups attached to chiral carbon atom is ______
Identify the chiral molecule from the following.
Identify chiral molecule/s from the following.
a.
\[\begin{array}{cc}
\ce{CH3 - CH - CH2 - CH3}\\
|\phantom{.........}\\
\ce{OH}\phantom{.......}
\end{array}\]
b.
\[\begin{array}{cc}
\ce{CH3 - CH2 - CH - CH2 - CH3}\\
|\phantom{.}\\
\ce{Br}\phantom{.}
\end{array}\]
c.
\[\ce{CH3 - CH - CH2 - CH2Br}\]
d.
\[\begin{array}{cc}
\ce{CH3 - CH - CH2 - CH3}\\
|\phantom{.........}\\
\ce{CH3}\phantom{......}
\end{array}\]
Identify chiral molecules from the following
a.
\[\begin{array}{cc}
\ce{CH3 - CH - CH2 - CH3}\\
|\phantom{.........}\\
\ce{OH}\phantom{.......}
\end{array}\]
b.
\[\begin{array}{cc}
\ce{CH3 - CH2 - CH - CH2 - CH3}\\
|\phantom{..}\\
\ce{Br}
\end{array}\]
c.
\[\begin{array}{cc}
\ce{CH3 - CH2 - CH2 - CH2Br}
\end{array}\]
d.
\[\begin{array}{cc}
\ce{CH3 - CH - CH3 - CH3}\\
|\phantom{.........}\\
\ce{CH3}\phantom{.......}
\end{array}\]
Identify chiral molecule/s from the following.
a.
\[\begin{array}{cc}
\ce{CH3 - CH - CH2 - CH3}\\
|\phantom{.........}\\
\ce{OH}\phantom{.......}
\end{array}\]
b.
\[\begin{array}{cc}
\ce{CH3 - CH2 - CH - CH2 - CH3}\\
|\phantom{.}\\
\phantom{.}\ce{Br}
\end{array}\]
c.
\[\ce{CH3 - CH2 - CH2 - CH2 Br}\]
d.
\[\begin{array}{cc}
\ce{CH3 - CH - CH3 - CH3}\\
|\phantom{.........}\\
\ce{CH3}\phantom{......}
\end{array}\]
Define the following:
Chirality
Identify the chiral molecule from the following.
Identify the chiral molecule from the following.
Identify chiral molecule/s from the following.
Identify the chiral molecule from the following:
Identify chiral molecule/s from the following.
Identify the chiral molecule from the following.
Identify chiral molecule/s from the following.
Identify the chiral molecule from the following.
Identify the chiral molecule from the following.
Identify chiral molecule/s from the following.
Identify the chiral molecule from the following.
Identify chiral molecule/s from the following.
Identify the chiral molecule from the following.
Sucrose in water is dextro-rotatory, [α]D = +66.4°. When boiled with dilute HCI, the solution becomes leavo-rotatory, [α] = −20°. In this process the sucrose molecule breaks into ______.
