Advertisements
Advertisements
प्रश्न
Evaluate:
`(x^(5+n)(x^2)^(3n+1))/x^(7n-2)`
Advertisements
उत्तर
`(x^(5+n)(x^2)^(3n+1))/x^(7n-2)`
Step 1: Simplify `(x^2)^(3n+1)`
Using the rule (am)n = am⋅n:
(x2)3n+1 = x2(3n+1) = x6n+2.
Step 2: Multiply x5+n and x6n+2
Using the product rule (am⋅an = am+n):
x5+n⋅x6n+2 = x(5+n)+(6n+2) = x5+n+6n+2 = x7+7n.
Step 3: Divide by x7n−2
Using the quotient rule `a^m/a^n = a^(m-n)`:
`x^(7+7n)/x^(7n-2)`
`= x^((7+7n)−(7n−2))`
`= x^(7+7n−7n+2)`
`= x^(7+2)`
`= x^9`
APPEARS IN
संबंधित प्रश्न
Compute:
`(2^-9÷2^-11)^3`
Compute:
`(-5)^4xx(-5)^6÷(-5)^9`
Compute:
`(27/64)^(-2/3)`
Evaluate:
`(7"x"^0)^2`
Simplify:
`"x"^10"y"^6÷"x"^3"y"^-2`
Simplify:
`5"z"^16÷15"z"^-11`
Simplify:
`(27"x"^-3"y"^6)^(2/3)`
Show that:
`(("x"^"a")/"x"^(-"b"))^("a"-"b").(("x"^"b")/"x"^(-"c"))^("b"-"c").(("x"^"c")/("x"^(-"a")))^("c"-"a")=1`
Prove that:
`1/(1+"x"^("a"-"b"))+1/(1+"x"^("b"-"a"))=1`
Find the value of n, when:
`("a"^(2"n"-3)xx("a"^2)^("n"+1))/(("a"^4)^-3)=("a"^3)^3÷("a"^6)^-3`
