Advertisements
Advertisements
प्रश्न
Evaluate:
`(x^(5+n)(x^2)^(3n+1))/x^(7n-2)`
Advertisements
उत्तर
`(x^(5+n)(x^2)^(3n+1))/x^(7n-2)`
Step 1: Simplify `(x^2)^(3n+1)`
Using the rule (am)n = am⋅n:
(x2)3n+1 = x2(3n+1) = x6n+2.
Step 2: Multiply x5+n and x6n+2
Using the product rule (am⋅an = am+n):
x5+n⋅x6n+2 = x(5+n)+(6n+2) = x5+n+6n+2 = x7+7n.
Step 3: Divide by x7n−2
Using the quotient rule `a^m/a^n = a^(m-n)`:
`x^(7+7n)/x^(7n-2)`
`= x^((7+7n)−(7n−2))`
`= x^(7+7n−7n+2)`
`= x^(7+2)`
`= x^9`
APPEARS IN
संबंधित प्रश्न
Compute:
`1^8xx3^0xx5^3xx2^2`
Compute:
`9^0xx4^-1÷2^-4`
Evaluate:
`8^0+4^0+2^0`
Evaluate:
`4"x"^0`
Simplify:
`("a"^5"b"^2)/("a"^2"b"^-3`
Simplify:
`"x"^10"y"^6÷"x"^3"y"^-2`
Simplify:
`(125"x"^-3)^(1/3)`
Simplify and express as positive indice:
(xy)(m-n).(yz)(n-l).(zx)(l-m)
Show that:
`(("x"^"a")/"x"^(-"b"))^("a"-"b").(("x"^"b")/"x"^(-"c"))^("b"-"c").(("x"^"c")/("x"^(-"a")))^("c"-"a")=1`
Prove that:
`((x^a)/x^b)^(1/(ab))((x^b)/x^c)^(1/(bc))(x^c/x^a)^(1/(ca))=1`
