Advertisements
Advertisements
प्रश्न
Evaluate:
`("a"^(2"n"+1)xx"a"^((2"n"+1)(2"n"-1)))/("a"^("n"(4"n"-1))xx("a"^2)^(2"n"+3)`
बेरीज
Advertisements
उत्तर
`("a"^(2"n"+1)xx"a"^((2"n"+1)(2"n"-1)))/("a"^("n"(4"n"-1))xx("a"^2)^(2"n"+3)`
`=("a"^(2"n"+1)xx"a"^(4"n"^2-1))/("a"^(4"n"^2-"n")xx"a"^(4"n+6"`
`="a"^(4"n"+2"n")/("a"^(4"n"^2+3"n"+6)`
`="a"^(4"n"^2+2n-(4n^2+3n+6)`
`="a"^(4"n"^2+2n-4n^2-3n-6)`
`="a"^(-"n"-6)`
`="a"^-("n"+6)`
`=1/("a"^("n"+6)`
shaalaa.com
More About Exponents
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Compute:
`(2^-9÷2^-11)^3`
Compute:
`(56/28)^0÷(2/5)^3xx16/25`
Compute:
`(-1/3)^4÷(-1/3)^8xx(-1/3)^5`
Compute:
`(625)^(-3/4)`
Compute:
`(125)^(-2/3)÷(8)^(2/3)`
Compute:
`(243)^(2/5)÷(32)^(-2/5)`
Simplify:
`(27"x"^-3"y"^6)^(2/3)`
Simplify:
`(-2"x"^(2/3)"y"^(-3/2))^6`
Evaluate:
`(x^(5+n)(x^2)^(3n+1))/x^(7n-2)`
Prove that:
`1/(1+"x"^("a"-"b"))+1/(1+"x"^("b"-"a"))=1`
