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Evaluate the definite integral: ∫012x+35x2+1dx

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प्रश्न

Evaluate the definite integral:

`int_0^1 (2x + 3)/(5x^2 + 1) dx`

योग
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उत्तर

Let `I = int_0^1  (2x + 3)/(5x^2 + 1)  dx`

`= int_0^1 (2x)/(5x^2 + 1)  dx +  int_0^1 3/(5x^2 + 1)  dx`

`= 1/5  int_0^1 (10 x)/(5x^2 + 1) dx + 3/5  int_0^1 1/(x^2 + 1/sqrt5)  dx`

`= 1/5  [log (5x^2 + 1)]_0^1 + 3/5 . 1/(1 sqrt5) [tan^-1 (x/ 1)/sqrt5]_0^1`

`= 1/5  [log 6 - log 1] + 3/sqrt5 [tan^-1 sqrt5 - tan^-1 0]`

`= 1/5  log 6 + 3/sqrt5  tan^-1 sqrt5`

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अध्याय 7: Integrals - Exercise 7.9 [पृष्ठ ३३८]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 7 Integrals
Exercise 7.9 | Q 14 | पृष्ठ ३३८

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