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प्रश्न
Evaluate the definite integral:
`int_0^1 dx/(1+x^2)`
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उत्तर
`int_0^1 dx/(1 + x^2)`
`= [tan^-1 x]_0^1`
`= tan^-1 (1) - tan^-1 0`
`= pi/4 - 0`
`= pi/4`
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