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Equal Torques Act on the Disc a and B of the Previous Problem, Initially Both Being at Rest

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प्रश्न

Equal torques act on the disc A and B of the previous problem, initially both being at rest. At a later instant, the linear speeds of a point on the rim of A and another point on the rim of B are \[\nu_A\] and \[\nu_B\] respectively. We have

विकल्प

  • \[\nu_A>\nu_B\]

  • \[\nu_A=\nu_B\]

  • \[\nu_A<\nu_B\]

  • the relation depends on the actual magnitude of the torques

MCQ
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उत्तर

\[\nu_A>\nu_B\]

 

\[\tau = I\alpha  \left(\text{magnitude} \right)\]

For equal torque, we have

\[I_A  \alpha_A  =  I_B  \alpha_B\]

IA < IB

⇒ \[\alpha_A  >  \alpha_B  ...........(1)\]

Now,

\[\omega = \alpha t\]

Or,

\[\frac{v}{r} = \alpha t\]

\[\nu_A    >    \nu_B.............\left(\text{Using (1)}\right)\]

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अध्याय 10: Rotational Mechanics - MCQ [पृष्ठ १९३]

APPEARS IN

एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 10 Rotational Mechanics
MCQ | Q 12 | पृष्ठ १९३

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