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A Heavy Particle of Mass M Falls Freely Near the Earth'S Surface. What is the Torque Acting on this Particle About a Point 50 Cm East to the Line of Motion? - Physics

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प्रश्न

A heavy particle of mass m falls freely near the earth's surface. What is the torque acting on this particle about a point 50 cm east to the line of motion? Does this torque produce any angular acceleration in the particle?

योग
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उत्तर

We know that
\[ \overrightarrow{\tau} = \overrightarrow{r} \times \overrightarrow{F} \]
Given:-
\[ \overrightarrow{r} = - 0 . 5 \hat i m\]
\[ \overrightarrow{F} = - mg \hat j \]
The torque becomes
\[ \overrightarrow{\tau} = 0 . 5\left( - \hat i \right) \times mg\left( - \hat j \right)\]
\[ \overrightarrow{\tau} = 0 . 5 \text{mg } \hat k \left[ \because \hat i \times \hat j = \hat k \right]\]
No, there will be no angular acceleration on the particle due to the torque.
Angular acceleration is given by \[\alpha = \frac{\tau}{I}\]. As the particle here moves in a straight line, the centre of rotation lies at a distance infinity \[(r = \infty );\] so, moment of inertia \[(I = m r^2 )\] of the particle is infinity.
\[ \therefore \alpha = 0\]

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अध्याय 10: Rotational Mechanics - Short Answers [पृष्ठ १९२]

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एचसी वर्मा Concepts of Physics Vol. 1 [English] Class 11 and 12
अध्याय 10 Rotational Mechanics
Short Answers | Q 8 | पृष्ठ १९२

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