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Find the components along the x, y, z axes of the angular momentum l of a particle, whose position vector is r with components x, y, z and momentum is - Physics

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प्रश्न

Find the components along the x, y, z axes of the angular momentum of a particle, whose position vector is with components x, y, z and momentum is with components px, py and 'p_z`. Show that if the particle moves only in the x-y plane the angular momentum has only a z-component.

संख्यात्मक
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उत्तर

lx = ypz – zpy

l= zpx – xpz

lz = xpy –ypx

Linear momentum of the particle,`vecp = p_x hati + p_y hatj + p_z hatk`

Position vector of the particle, `vecr = xhati + yhatj + zhatk`

Angular momentum, `hatl = hatr xx hatp`

=`(xhati + yhatj + zhatk) xx (p_x hati + p_y hatj + p_z hatk)`

`=|(hati,hatj,hatk),(x,y,z), (p_x, p_y,p_z)|`

`l_xhati + l_yhatj + l_z hatk = hati (yp_z - zp_y) - hatj(xp_z - zp_x) + hatk (xp_y - zp_x)`

Comparing the coefficients of `hati, hatj, hatk` we get:

 `((l_x = yp_z - zp_y),(l_y = xp_z -zp_x),(l_z = xp_y - yp_x))}...(i)`

The particle moves in the x-y plane. Hence, the z-component of the position vector and linear momentum vector becomes zero, i.e.,

z = pz = 0

Thus, equation (i) reduces to:

`((l_x=0),(l_y=0),(l_z=xp_y -yp_x))} `

Therefore, when the particle is confined to move in the x-y plane, the direction of angular momentum is along the z-direction.

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अध्याय 6: System of Particles and Rotational Motion - EXERCISES [पृष्ठ १२५]

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एनसीईआरटी Physics [English] Class 11
अध्याय 6 System of Particles and Rotational Motion
EXERCISES | Q 6.6 | पृष्ठ १२५

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