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प्रश्न
Draw a line segment of given length and construct a perpendicular bisector to line segment using scale and compass
8 cm
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उत्तर
Construction:
Step 1: Drawn a line. Marked two points A and B on it so that AB = 8 cm
Step 2: Using compass with A as centre and radius more than half of the length of AB, drawn two arcs of the same length one above AB and one below AB
Step 3: With the same radius and B as centre drawn two arcs to cut the arcs drawn in step 2.
Marked the points of intersection of the arcs as C and D.
Step 4: Joined C and D, CD intersect AB. Marked the point of intersection as ‘O’.
CD is the required perpendicular bisector of AB.
AO = OB
= `8/2`
= 4 cm, ∠AOC = 90°
APPEARS IN
संबंधित प्रश्न
In each of the following, draw perpendicular through point P to the line segment AB :
(i)
(ii)
(iii)
Draw a line segment of given length and construct a perpendicular bisector to line segment using scale and compass
7 cm
Only one perpendicular bisector can be drawn to a given line segment.
In the following figure, the point C is the image of point A in line l and line segment BC intersects the line l at P.
- Is the image of P in line l the point P itself?
- Is PA = PC?
- Is PA + PB = PC + PB?
- Is P that point on line l from which the sum of the distances of points A and B is minimum?
Draw a line segment of length 7 cm. Draw its perpendicular bisector, using ruler and compasses.
Draw a line segment of length 6.5 cm and divide it into four equal parts, using ruler and compasses.
Bisect ∠XYZ of figure.
Bisect a straight angle, using ruler and compasses. Measure each part.
Draw a line segment of length 10 cm. Divide it into four equal parts. Measure each of these parts.
Which two conditions, when combined, define the Perpendicular Bisector of a line segment AB?
