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प्रश्न
Draw a line segment PQ = 4.8 cm. Construct the perpendicular bisector of PQ.
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उत्तर
Steps of Construction :
- Draw a line segment PQ = 4.8 cm.
- With P as centre and radius equal than half of PQ, draw an arc on both the PQ.
- With Q as the centre and the same radius as taken in step 2, draw arcs on both sides of PQ.
- Let the arcs intersect each other at point A and B
- Join A and B.
- The line AB cuts the line segment PQ at the point O. Here OP = OQ and ∠AOQ = 90°. Then the line AB is a perpendicular bisector of PQ.
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संबंधित प्रश्न
The line of symmetry of a line segment is the ______ bisector of the line segment.
Only one perpendicular bisector can be drawn to a given line segment.
Infinitely many perpendiculars can be drawn to a given ray.
In the following figure, the point C is the image of point A in line l and line segment BC intersects the line l at P.
- Is the image of P in line l the point P itself?
- Is PA = PC?
- Is PA + PB = PC + PB?
- Is P that point on line l from which the sum of the distances of points A and B is minimum?
Draw a line segment of length 7 cm. Draw its perpendicular bisector, using ruler and compasses.
Copy figure on your notebook and draw a perpendicular from P to line m, using (i) set squares (ii) protractor (iii) ruler and compass. How many such perpendicular are you able to draw?
Bisect ∠XYZ of figure.
Repeat Question 6, if `overline"AB"` happens to be a diameter.
What property defines the Uniqueness of the perpendicular bisector?
If point X lies on the perpendicular bisector of segment AB, then:
