Question

Divide −4a³ + 4a² + a by 2a.

Answer 1

\[\frac{- 4 a^3 + 4 a^2 + a}{2a}\]
\[ = \frac{- 4 a^3}{2a} + \frac{4 a^2}{2a} + \frac{a}{2a}\]
\[ = - 2 a^{(3 - 1)} + 2 a^{(2 - 1)} + \frac{1}{2}\]
\[ = - 2 a^2 + 2a + \frac{1}{2}\]