Advertisements
Advertisements
प्रश्न
Using division of polynomials, state whether
3y2 + 5 is a factor of 6y5 + 15y4 + 16y3 + 4y2 + 10y − 35
योग
Advertisements
उत्तर

Remainder is zero. Therefore, 3y2 + 5 is a factor of
\[6 y^5 + 15 y^4 + 16 y^3 + 4 y^2 + 10y - 35\]
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Write the degree of each of the following polynomials.
2x + x2 − 8
Write the degree of each of the following polynomials.
5
Write each of the following polynomials in the standard form. Also, write their degree.
x2 + 3 + 6x + 5x4
Simplify:\[\frac{32 m^2 n^3 p^2}{4mnp}\]
Divide x + 2x2 + 3x4 − x5 by 2x.
Divide 3x3y2 + 2x2y + 15xy by 3xy.
Divide x5 + x4 + x3 + x2 + x + 1 by x3 + 1.
Verify the division algorithm i.e. Dividend = Divisor × Quotient + Remainder, in each of the following. Also, write the quotient and remainder.
| Dividend | Divisor |
| 15y4 − 16y3 + 9y2 −\[\frac{10}{3}\] y+6 | 3y − 2 |
Divide:
(a2 + 2ab + b2) − (a2 + 2ac + c2) by 2a + b + c
8x3y ÷ 4x2 = 2xy
