Advertisements
Advertisements
प्रश्न
Find whether the first polynomial is a factor of the second.
4y + 1, 8y2 − 2y + 1
Advertisements
उत्तर
\[\frac{{8y}^2 -2y+1}{4y+1}\]
\[ = \frac{2y (4y+1)-1(4y+1)+2}{4y+1}\]
\[ = \frac{(4y+1)(2y-1)+2}{4y+1}\]
\[ = (2y-1)+ \frac{2}{4y+1}\]
\[ \because \text{Remainder = 2}\]
\[ \therefore \text{( 4y+1) is not a factor of}\ {8y}^2 -2y+1.\]
APPEARS IN
संबंधित प्रश्न
Divide the given polynomial by the given monomial.
(3y8 − 4y6 + 5y4) ÷ y4
Write each of the following polynomials in the standard form. Also, write their degree.
(x3 − 1)(x3 − 4)
Divide −21abc2 by 7abc.
Divide −72a4b5c8 by −9a2b2c3.
Simplify:\[\frac{32 m^2 n^3 p^2}{4mnp}\]
Divide 5x3 − 15x2 + 25x by 5x.
Divide −21 + 71x − 31x2 − 24x3 by 3 − 8x.
Divide 14x3 − 5x2 + 9x − 1 by 2x − 1 and find the quotient and remainder
Divide 30x4 + 11x3 − 82x2 − 12x + 48 by 3x2 + 2x − 4 and find the quotient and remainder.
Verify the division algorithm i.e. Dividend = Divisor × Quotient + Remainder, in each of the following. Also, write the quotient and remainder.
| Dividend | Divisor |
| 34x − 22x3 − 12x4 − 10x2 − 75 | 3x + 7 |
