Advertisements
Advertisements
प्रश्न
Find whether the first polynomial is a factor of the second.
4y + 1, 8y2 − 2y + 1
Advertisements
उत्तर
\[\frac{{8y}^2 -2y+1}{4y+1}\]
\[ = \frac{2y (4y+1)-1(4y+1)+2}{4y+1}\]
\[ = \frac{(4y+1)(2y-1)+2}{4y+1}\]
\[ = (2y-1)+ \frac{2}{4y+1}\]
\[ \because \text{Remainder = 2}\]
\[ \therefore \text{( 4y+1) is not a factor of}\ {8y}^2 -2y+1.\]
संबंधित प्रश्न
Divide −21abc2 by 7abc.
Simplify:\[\frac{16 m^3 y^2}{4 m^2 y}\]
Divide 9x2y − 6xy + 12xy2 by −\[\frac{3}{2}\]
Divide x2 + 7x + 12 by x + 4.
Using division of polynomials, state whether
z2 + 3 is a factor of z5 − 9z
Find the value of a, if x + 2 is a factor of 4x4 + 2x3 − 3x2 + 8x + 5a.
What must be added to x4 + 2x3 − 2x2 + x − 1 , so that the resulting polynomial is exactly divisible by x2 + 2x − 3?
Find whether the first polynomial is a factor of the second.
4 − z, 3z2 − 13z + 4
Divide:
ax2 − ay2 by ax + ay
Divide 24(x2yz + xy2z + xyz2) by 8xyz using both the methods.
