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D 20 D X 20 ( 2 Cos X Cos 3 X ) = (A) 220 (Cos 2 X − 220 Cos 4 X) (B) 220 (Cos 2 X + 220 Cos 4 X) - Mathematics

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प्रश्न

\[\frac{d^{20}}{d x^{20}} \left( 2 \cos x \cos 3 x \right) =\]

 

विकल्प

  • 220 (cos 2 x − 220 cos 4 x)

  • 220 (cos 2 x + 220 cos 4 x)

  • 220 (sin 2 x + 220 sin 4 x)

  • 220 (sin 2 x − 220 sin 4 x)

MCQ
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उत्तर

(b) 220(cos2x + 220cos4x)

Here,

\[y = 2\cos x \cos3x = \cos\left( 3x - x \right) + \cos\left( 3x + x \right)\]

\[ = \cos2x + \cos4x\]

\[ \Rightarrow \frac{d y}{d x} = - 2 \sin2x - 4 \sin4x = - 2\left( \sin2x + 2 \sin4x \right)\]

\[ \Rightarrow \frac{d^2 y}{d x^2} = - 4 \cos2x - 16 \cos4x = - 2^2 \left( \cos2x + 2^2 \cos4x \right)\]

\[ \Rightarrow \frac{d^3 y}{d x^3} = 2^3 \left( \sin2x + 2^3 \sin4x \right)\]

\[ \Rightarrow \frac{d^4 y}{d x^4} = 2^3 \left( 2\cos2x + 4 \times 2^3 \cos4x \right) = 2^4 \left( \cos2x + 2^4 \cos4x \right)\]

\[ \therefore \frac{d^{20} \left( \cos2x + \cos4x \right)}{d x^{20}} = 2^{20} \left( \cos2x + 2^{20} \cos4x \right)\]

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अध्याय 12: Higher Order Derivatives - Exercise 12.3 [पृष्ठ २३]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 12 Higher Order Derivatives
Exercise 12.3 | Q 4 | पृष्ठ २३

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