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If F ( X ) = √ X 2 − 10 X + 25 Then the Derivative of F (X) in the Interval [0, 7] is (A) 1 (B) −1 - Mathematics

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प्रश्न

If \[f\left( x \right) = \sqrt{x^2 - 10x + 25}\]  then the derivative of f (x) in the interval [0, 7] is ____________ .

विकल्प

  • 1

  • -1

  • 0

  • none of these

MCQ
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उत्तर

none of these

 

\[\text { We have, } f\left( x \right) = \sqrt{x^2 - 10x + 25}\]
\[ = \sqrt{\left( x - 5 \right)^2}\]
\[ = \left| x - 5 \right| \]
`={[x-5 " for " x>5],[-(x-5) " for " x<5]:}`
\[\text { LHD }= \lim_{x \to 5^-} \frac{f\left( x \right) - f\left( a \right)}{x - a}\]
\[ = \lim_{x \to 5^-} \frac{\sqrt{x^2 - 10x + 25} - \sqrt{5^2 - 10\left( 5 \right) + 25}}{x - 5}\]
\[ = \lim_{x \to 5^-} \frac{\left| x - 5 \right|}{x - 5}\]
\[ = \lim_{x \to 5^-} \frac{- \left( x - 5 \right)}{x - 5}\]
\[ = - 1\]
\[RHD = \lim_{x \to 5^+} \frac{f\left( x \right) - f\left( a \right)}{x - a}\]
\[ = \lim_{x \to 5^+} \frac{\sqrt{x^2 - 10x + 25} - \sqrt{5^2 - 10\left( 5 \right) + 25}}{x - 5}\]
\[ = \lim_{x \to 5^+} \frac{\left| x - 5 \right|}{x - 5}\]
\[ = \lim_{x \to 5^+} \frac{x - 5}{x - 5}\]
\[ = 1\]
\[\text { Here, LHD } \neq RHD\]
\[\text { Thus, the function is not differentiable at }x = 5\]

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अध्याय 11: Differentiation - Exercise 11.10 [पृष्ठ १२१]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 11 Differentiation
Exercise 11.10 | Q 23 | पृष्ठ १२१

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