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प्रश्न
Differentiate sin(log sin x) ?
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उत्तर
Let y = sin (log sin x)
Differentiate it with respect to x We get,
`(dy)/(dx)=d/(dx)sin (log sin x)`
`=cos (log sin x)d/(dx)(log sin x)` [Using chain rule]
`=cos (log sin x)xx1/(sin x)d/(dx)sin x` [Using chain rule]
`=cos (log sin x)(cos x)/(sin x)`
`=cos (log sin x) cot x`
Hence, `d/(dx)sin (log sin x) = cos (log sin x) cot x`
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