हिंदी

Consider two conducting wires A and B of the same diameter but made of different materials joined in series across a battery. The number density of electrons in A is 1.5 times that in B.

Advertisements
Advertisements

प्रश्न

Consider two conducting wires A and B of the same diameter but made of different materials joined in series across a battery. The number density of electrons in A is 1.5 times that in B. Find the ratio of the drift velocity of electrons in wire A to that in wire B.

संख्यात्मक
Advertisements

उत्तर

In a series circuit current flowing through the entire circuit is exactly the same, hence

`I = n_A A_e(v_d)_A`

= `n_B A_e(v_d)_B`

`((v_d)_A)/((v_d)_B) = n_B/n_A = n_B/(1.5n_B) = 1/1.5`

= `10/15 = 2/3`

`(v_d)_A : (v_d)_B = 2 : 3`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2022-2023 (March) Delhi Set 1

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Define the term drift velocity.


Derive an expression for  drift velocity of free electrons.


Estimate the average drift speed of conduction electrons in a copper wire of cross-sectional area 1.0 × 10−7 m2 carrying a current of 1.5 A. Assume the density of conduction electrons to be 9 × 1028 m−3


Explain the term ‘drift velocity’ of electrons in conductor. Hence obtain the expression for the current through a conductor in terms of ‘drift velocity’. 


Define relaxation time of the free electrons drifting in a conductor. How is it related to the drift velocity of free electrons? Use this relation to deduce the expression for the electrical resistivity of the material.


Derive an expression for drift velocity of free electrons in a conductor in terms of relaxation time.


Electrons are emitted by a hot filament and are accelerated by an electric field, as shown in the figure. The two stops at the left ensure that the electron beam has a uniform cross-section.


Consider a wire of length 4 m and cross-sectional area 1 mm2 carrying a  current of 2 A. If each cubic metre of the material contains 1029 free electrons, find the average time taken by an electron to cross the length of the wire.


The relaxation time τ is nearly independent of applied E field whereas it changes significantly with temperature T. First fact is (in part) responsible for Ohm’s law whereas the second fact leads to variation of ρ with temperature. Elaborate why?


A potential difference (V) is applied across a conductor of length 'L' and cross-sectional area 'A'.

How will the drift velocity of electrons and the current density be affected if another identical conductor of the same material were connected in series with the first conductor? Justify your answers.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×