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प्रश्न
Chlorobenzene is extremely less reactive towards a nucleophilic substitution reaction. Give two reasons for the same.
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उत्तर
Chlorobenzene is extremely less reactive towards a nucleophilic substitution reaction because of the following reasons:
(1) Resonance effect: The electron pair on chlorine atom is in conjugation with the π - electrons of the benzene ring which results in the following resonance structures:

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This results in delocalization of the electrons of C − Cl bond and a partial double bond character develops in the bond, which makes it difficult for the nucleophile to cleave the C − Cl bond.
(2) The nucleophile suffers repulsion from the increased electron density on the benzene ring as a result the nucleophile is unable to make a close approach for the attack on the molecule.
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संबंधित प्रश्न
The presence of nitro group (−NO2) at o/p positions increases the reactivity of haloarenes towards nucleophilic substitution reactions.
How the following conversion can be carried out?
Chlorobenzene to p-nitrophenol
What is Grignard reagent?
Write chemical equation in support of your answer.
Out of
Cl and
CH2- Cl, which one is more reactive towards nucleophilic substitution reaction and why?
Assertion: Presence of a nitro group at ortho or para position increases the reactivity of haloarenes towards nucleophilic substitution.
Reason: Nitro group, being an electron-withdrawing group decreases the electron density over the benzene ring.
Arrange the following compounds in increasing order of rate of reaction towards nucleophilic substitution.
| (a) | ![]() |
| (b) | ![]() |
| (c) | ![]() |
Haloarenes are less reactive than haloalkanes and haloalkenes. Explain.
Allyl chloride is hydrolysed more readily than n-propyl chloride. Why?
Assertion: Chlorobenzene is resistant to nucleophilic substitution reaction at room temperature.
Reason (R): C–Cl bond gets weaker due, to resonance.
Identify the final product [D] obtained in the following sequence of reactions.
\[\ce{CH3CHO \underset{ii) H2O+}{\overset{i) LiAlH4}{->}} [A] \underset{\triangle}{\overset{H2SO4}{->}} [B]}\]




