Advertisements
Advertisements
प्रश्न
“Caste inequalities are still prevalent in India.” Examine the statement.
Advertisements
उत्तर
Caste inequalities have not completely disappeared from India. Even today, most people marry within their own caste or tribe. Despite the constitutional prohibition, Untouchability has not ended completely. Education is not easily available to the so-called ‘low castes’. Economic status is closely linked to the caste system. In modern India, like in pre-independence India, the poor are mostly the ‘low castes’, while the rich are the ‘high castes’, thereby showing that caste inequalities are still continuing.
APPEARS IN
संबंधित प्रश्न
ABC is a triangle. Locate a point in the interior of ΔABC which is equidistant from all the vertices of ΔABC.
Complete the hexagonal and star shaped rangolies (see the given figures) by filling them with as many equilateral triangles of side 1 cm as you can. Count the number of triangles in each case. Which has more triangles?

Arrange the sides of ∆BOC in descending order of their lengths. BO and CO are bisectors of angles ABC and ACB respectively.

In the following figure, ∠BAC = 60o and ∠ABC = 65o.

Prove that:
(i) CF > AF
(ii) DC > DF
"Issues of caste discrimination began to be written about in many printed tracts and essays in India in the late nineteenth century." Support the statement with two suitable examples.
Name the greatest and the smallest sides in the following triangles:
ΔDEF, ∠D = 32°, ∠E = 56° and ∠F = 92°.
In ΔABC, the exterior ∠PBC > exterior ∠QCB. Prove that AB > AC.
Prove that the hypotenuse is the longest side in a right-angled triangle.
ABCD is a quadrilateral in which the diagonals AC and BD intersect at O. Prove that AB + BC + CD + AD < 2(AC + BC).
In ΔABC, AE is the bisector of ∠BAC. D is a point on AC such that AB = AD. Prove that BE = DE and ∠ABD > ∠C.
