हिंदी

Calculate the velocity of a particle performing S.H.M. after 1 second, if its displacement is given by x = 5sin(πt3)m.

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प्रश्न

Calculate the velocity of a particle performing S.H.M. after 1 second, if its displacement is given by x = `5sin((pit)/3)`m.

योग
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उत्तर १

Given:

x = `5sin((pit)/3)`m

t = 1s

∴ ν = `(dx)/(dt) = d/dt(5sin((pit)/3)) = 5cos((pit)/3) xx pi/3`

Put t = 1s ...(Given)

∴ ν = `5cos(pi/3) xx pi/3` = 2.6179 m/s

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उत्तर २

t = 1s, x = 5 sin60

A = 5, x = `2.5sqrt3` ...........(given)

v = `wsqrt(A^2 - x^2)` .........(Formula)

v = `pi/3sqrt(25 - 18.74)`

v = 1.04 × 2.5

v = 2.61 m/s

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