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Calculate the standard enthalpy of the reaction: SiO2(s) + 3C(graphite) → SiC(s) + 2CO(g) from the following reactions: Si(s) + O2(g) → SiO2(s),

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प्रश्न

Calculate the standard enthalpy of the reaction, \[\ce{SiO2_{(s)} + 3C_{(graphite)} -> SiC_{(s)} + 2CO_{(g)}}\] from the following reactions:

  1. \[\ce{Si_{(s)} + O2_{(g)} -> SiO2_{(s)}}\], ΔrH0 = −911 kJ
  2. \[\ce{2C_{(graphite)} + O2_{(g)} -> 2CO_{(g)}}\], ΔrH= −221 kJ
  3. \[\ce{Si_{(s)} + C_{(graphite)} -> SiC_{(s)}}\], ΔrH= −65.3 kJ
रासायनिक समीकरण/संरचनाएँ
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उत्तर

Reverse the Eq. (i)

(iv) \[\ce{SiO2_{(s)} -> Si_{(s)} + O2_{(g)}}\], ΔrH0 = −911 kJ

Add equations (ii), (iii) and (iv)

(ii) \[\ce{2C_{(graphite)} + O2_{(g)} -> 2CO_{(g)}}\], ΔrH= −221 kJ

(iii) \[\ce{Si_{(s)} + C_{(graphite)} -> SiC_{(s)}}\], ΔrH= −65.3 kJ

(iv) \[\ce{SiO2_{(s)} -> Si_{(s)} + O2_{(g)}}\], ΔrH0 = −911 kJ
________________________________________________

\[\ce{SiO2_{(s)} + 3C_{(graphite)} → SiC_{(s)} + 2 CO_{(g)}}\], ΔrH= +624 kJ

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