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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Calculate the standard enthalpy of the reaction: SiO2(s) + 3C(graphite) → SiC(s) + 2CO(g) from the following reactions: Si(s) + O2(g) → SiO2(s),

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प्रश्न

Calculate the standard enthalpy of the reaction, \[\ce{SiO2_{(s)} + 3C_{(graphite)} -> SiC_{(s)} + 2CO_{(g)}}\] from the following reactions:

  1. \[\ce{Si_{(s)} + O2_{(g)} -> SiO2_{(s)}}\], ΔrH0 = −911 kJ
  2. \[\ce{2C_{(graphite)} + O2_{(g)} -> 2CO_{(g)}}\], ΔrH0 = −221 kJ
  3. \[\ce{Si_{(s)} + C_{(graphite)} -> SiC_{(s)}}\], ΔrH0 = −65.3 kJ
रासायनिक समीकरणे/रचना
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उत्तर

Reverse the Eq. (i)

(iv) \[\ce{SiO2_{(s)} -> Si_{(s)} + O2_{(g)}}\], ΔrH0 = −911 kJ

Add equations (ii), (iii) and (iv)

(ii) \[\ce{2C_{(graphite)} + O2_{(g)} -> 2CO_{(g)}}\], ΔrH0 = −221 kJ

(iii) \[\ce{Si_{(s)} + C_{(graphite)} -> SiC_{(s)}}\], ΔrH0 = −65.3 kJ

(iv) \[\ce{SiO2_{(s)} -> Si_{(s)} + O2_{(g)}}\], ΔrH0 = −911 kJ
________________________________________________

\[\ce{SiO2_{(s)} + 3C_{(graphite)} → SiC_{(s)} + 2 CO_{(g)}}\], ΔrH0 = +624 kJ

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संबंधित प्रश्‍न

Answer in brief.

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Enthalpy for the given reaction will be:

\[\begin{array}{cc}
\phantom{}\ce{H}\phantom{...}\ce{H}\phantom{...................}\ce{H}\phantom{...}\ce{H}\phantom{....}\\
\phantom{.}|\phantom{....}|\phantom{....................}|\phantom{....}|\phantom{.....}\\
\ce{C = C + H - H -> H - C - C - H}\\
\phantom{.}|\phantom{....}|\phantom{....................}|\phantom{....}|\phantom{.....}\\
\phantom{}\ce{H}\phantom{...}\ce{H}\phantom{...................}\ce{H}\phantom{...}\ce{H}\phantom{....}
\end{array}\]


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