Advertisements
Advertisements
प्रश्न
Calculate the shortest wavelength of electromagnetic radiation present in Balmer series of hydrogen spectrum.
Calculate the shortest wavelength of Balmer series.
Advertisements
उत्तर
For shortest wavelength in Balmer series, nf = 2, ni = ∞
`1/lambda = R [1/n_f^2 - 1/n_i^2]`
`1/lambda = R(1/(2)^2 -0)`
`1/lambda = R/4`
∴ `lambda = 4/"R"`
∴ R = 1.097 × 107 m−1
` = 4/(1.097 xx 10^7) m`
` = 3.646 xx 10^-7 m`
= 3646 Å
= 364 nm
संबंधित प्रश्न
State an additional use of the X-rays waves
(a) Give a list of at least five radiations, in order of their increasing frequencies, which make up the complete electromagnetic spectrum.
(b) Which of the radiation mentioned by you in part (a) has the highest penetrating power.
What is the range of the wavelength of the following electromagnetic waves?
(A) Radio waves.
Name the waves produced by the changes in the nucleus of an atom.
Write the range of the wavelength of the following electromagnetic radiations:
(a) Infrared rays
(b) Ultraviolet rays
(c) γ -rays
Write one use of each of the above.
Define the term "Intensity" in the photon picture of electromagnetic radiation.
Identify the part of the electromagnetic spectrum used in
(i) radar and
(ii) eye surgery. Write their frequency range.
The ratio of contributions made by the electric field and magnetic field components to the intensity of an EM wave is ______.
What happens to the intensity of light from a bulb if the distance from the bulb is doubled? As a laser beam travels across the length of a room, its intensity essentially remains constant. What geometrical characteristic of LASER beam is responsible for the constant intensity which is missing in the case of light from the bulb?
Name one radiation having the wavelength longer than the wavelength of these radiations.
