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प्रश्न
Calculate the energy and frequency of the radiation emitted when an electron jumps from n = 3 to n = 2 in a hydrogen atom.
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उत्तर
We have `bar(v) = 109766 [1/n_i^2 - 1/n_f^2]`
Given, ni = 3 and nf =2
ΔE = `hcbar(v) = 109677 [1/n_i^2 - 1/n_f^2]`
ΔE = `- 3.052 xx 10^-19` J
v = `(ΔE)/h -= 4.606 xx 10^16` Hz
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