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Calculate the energy and frequency of the radiation emitted when an electron jumps from n = 3 to n = 2 in a hydrogen atom.

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प्रश्न

Calculate the energy and frequency of the radiation emitted when an electron jumps from n = 3 to n = 2 in a hydrogen atom.

दीर्घउत्तर
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उत्तर

We have `bar(v) = 109766 [1/n_i^2 - 1/n_f^2]`

Given, ni = 3 and nf =2

ΔE = `hcbar(v) = 109677 [1/n_i^2 - 1/n_f^2]`

ΔE = `- 3.052 xx 10^-19` J

v = `(ΔE)/h -= 4.606 xx 10^16` Hz

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अध्याय 2: Structure of Atom - Multiple Choice Questions (Type - I) [पृष्ठ २३]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 11
अध्याय 2 Structure of Atom
Multiple Choice Questions (Type - I) | Q 54 | पृष्ठ २३

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