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Calculate Magnetic Flux Density of the Magnetic Field at the Centre of a Circular Coil of 50 Turns, Having a Radius of 0.5m and Carrying a Current of 5 A.

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प्रश्न

Calculate magnetic flux density of the magnetic field at the centre of a circular coil of 50 turns, having a radius of 0.5m and carrying a current of 5 A.

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उत्तर

N = 50 turns, Radius r = 0.5 m, Current I = 5 A 

∴ Magnetic flux density at centre = B =`(mu_0NI)/(2a)`

                                                      =`(4pi xx10^-7 xx 50xx5)/(2xx0.5) T`

                                                      =`2pi xx 10^-7 xx 500  T` 

                                                   B = 3.14 × 10-4 T  

  or                                              B = 10-4 π T

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2016-2017 (March)

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