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Briefly Explain the Three Observed Features Which Can Be Explained by Einstein’S Photoelectric Equation. - Physics

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प्रश्न

Briefly explain the three observed features which can be explained by Einstein’s photoelectric equation.

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उत्तर

Three observed features which can be explained by this equation are:

(i) Solar cells: Also called photo-voltaic cells. It converts solar radiations to electrical emf.

(ii) Television telecast: The dark and bright light part of images are interpreted as high and low electrical charges as given by photoelectric emission principle. These are further processed and transmitted.

(iii) Burglar alarm: The moment the ultraviolet radiation is cut due to theif, it stops the supply of photons and thus works as ‘off’ mode and the ring bells automatically.

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Einstein’s Photoelectric Equation: Energy Quantum of Radiation
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2012-2013 (March) All India Set 1

संबंधित प्रश्न

Write Einstein’s photoelectric equation?


Is p − E/c valid for electrons?


A monochromatic light source of intensity 5 mW emits 8 × 1015 photons per second. This light ejects photoelectrons from a metal surface. The stopping potential for this setup is 2.0 V. Calculate the work function of the metal.

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


Consider the situation of the previous problem. Consider the faster electron emitted parallel to the large metal plate. Find the displacement of this electron parallel to its initial velocity before it strikes the large metal plate.

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


According to Einstein's photoelectric equation, the plot of the kinetic energy of the emitted photoelectrons from a metal versus the frequency of the incident radiation gives a straight line, whose slope ______.


Each photon has the same speed but different ______.


  1. In the explanation of photo electric effect, we assume one photon of frequency ν collides with an electron and transfers its energy. This leads to the equation for the maximum energy Emax of the emitted electron as Emax = hν – φ where φ0 is the work function of the metal. If an electron absorbs 2 photons (each of frequency ν) what will be the maximum energy for the emitted electron?
  2. Why is this fact (two photon absorption) not taken into consideration in our discussion of the stopping potential?

A student performs an experiment on photoelectric effect, using two materials A and B. A plot of Vstop vs ν is given in Figure.

  1. Which material A or B has a higher work function?
  2. Given the electric charge of an electron = 1.6 × 10–19 C, find the value of h obtained from the experiment for both A and B.

Comment on whether it is consistent with Einstein’s theory:


Radiation of frequency 1015 Hz is incident on three photosensitive surfaces A, B and C. Following observations are recorded:

Surface A: no photoemission occurs

Surface B: photoemission occurs but the photoelectrons have zero kinetic energy.

Surface C: photo emission occurs and photoelectrons have some kinetic energy.
Using Einstein’s photo-electric equation, explain the three observations.


A photon of wavelength 663 nm is incident on a metal surface. The work function of the metal is 1.50 eV. The maximum kinetic energy of the emitted photoelectrons is ______.


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