Advertisements
Advertisements
प्रश्न
Bond dissociation enthalpy of E–H (E = element) bonds is given below. Which of the compounds will act as the strongest reducing agent?
| Compound | \[\ce{NH3}\] | \[\ce{PH3}\] | \[\ce{AsH3}\] | \[\ce{SbH3}\] |
| Δdiss (E – H)/kJ mol–1 | 389 | 322 | 297 | 255 |
विकल्प
\[\ce{NH3}\]
\[\ce{PH3}\]
\[\ce{AsH3}\]
\[\ce{SbH3}\]
Advertisements
उत्तर
\[\ce{SbH3}\]
Explanation:
\[\ce{SbH3}\] will act as strongest reducing agent due to minimum bond enthalpy.
APPEARS IN
संबंधित प्रश्न
Iodine exists as
- polar molecular solid
- ionic solid
- nonpolar molecular solid
- hydrogen bonded molecular solid
Account for the following: Fluorine does not exhibit positive oxidation state.
Account for the following :
Acidic character increases from HF to HI.
Which halogen compound in each of the following pairs will react faster in SN2 reaction
(CH3)3 C – Cl or CH3 – Cl
Give two examples to show the anomalous behaviour of fluorine.
Write two uses of ClO2.
Arrange the following in the order of property indicated for the given set:
HF, HCl, HBr, HI - increasing acid strength.
Complete the following equations:
KMnO4 
Tincture of iodine is ____________.
Which one has the lowest boiling point?
The set with the correct order of acidity is:
In solid state \[\ce{PCl5}\] is a ______.
Reduction potentials of some ions are given below. Arrange them in decreasing order of oxidising power.
| Ion | \[\ce{CIO^{-}_{4}}\] | \[\ce{IO^{-}_{4}}\] | \[\ce{BrO^{-}_{4}}\] |
| Reduction potential EΘ/V |
EΘ = 1.19 V | EΘ = 1.65V | EΘ = 1.74 V |
Solubility of iodine in water may be increase by adding
Write the name and formula of oxoacid of fluorine.
Give a reason for the following:
Mn+2 compounds are more stable than Fe+2 compounds.
Arrange the following in the increasing order of the property mentioned:
MF, MCl, MBr, MI (ionic character)
