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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Boiling point of water at 750 mm Hg is 99.63°C. How much sucrose is to be added to 500 g of water such that it boils at 100°C? Molal elevation constant for water is 0.52 K kg mol−1.

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प्रश्न

Boiling point of water at 750 mm Hg is 99.63°C. How much sucrose is to be added to 500 g of water such that it boils at 100°C? Molal elevation constant for water is 0.52 K kg mol−1.

Boiling point of water at 750 mm Hg is 99.63°C. How much sucrose is to be added to 500 g of water such that it boils at 100°C?

संख्यात्मक
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उत्तर

Here, elevation of boiling point (ΔTb) = (100 + 273) − (99.63 + 273)

= 0.37 K

Mass of water (w1) = 500 g

Molar mass of sucrose (C12H22O11), M2 = 11 × 12 + 22 × 1 + 11 × 16

 = 342 g mol−1

Molal elevation constant (Kb) = 0.52 K kg mol−1

We know that,

ΔTb = `(K_b xx 1000 xx w_2)/(M_2 xx w_1)`

⇒ w2 = `(Delta T_b xx M_2 xx w_1)/(K_b xx 1000)`

= `(0.37 xx 342 xx 500)/(0.52 xx 1000)`

= 121.67 g (approximately)

= 122 g

Hence, 122 g of sucrose is to be added.

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अध्याय 1: Solutions - Intext Questions [पृष्ठ २३]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
अध्याय 1 Solutions
Intext Questions | Q 1.10 | पृष्ठ २३

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