हिंदी

Arrange the Following Increasing Order of Their Boiling Point: Ch3ch2oh,Ch3cho,Ch3 - O - Ch3

Advertisements
Advertisements

प्रश्न

 Arrange the following increasing order of their boiling point:
CH3CH2OH, CH3CHO, CH3–O–CH

एक पंक्ति में उत्तर
Advertisements

उत्तर

The order of boiling point :
 
CH3–O–CH3 < CH3CHO < CH3CH2OH

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2018-2019 (March) 56/3/2

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

8 g of glucose, C6H12O6 (Molar Mass = 180 g mol−1) is dissolved in 1 kg of water in a sauce pan. At what temperature will this solution boil? 

(Kb for water = 0.52 K kg mol−1, boiling point of pure water = 373.15 K)


Out of 1 M glucose and 2 M glucose, which one has a higher boiling point and why?


Define the following term: 

Colligative properties


People add sodium chloride to water while boiling eggs. This is to ____________.


Which of the following aqueous solutions should have the highest boiling point?


Why is it not possible to obtain pure ethanol by fractional distillation? What general name is given to binary mixtures which show deviation from Raoult’s law and whose components cannot be separated by fractional distillation. How many types of such mixtures are there?


Calculate the molal elevation constant for water given that 0.2 molal solution of non-volatile and non-electrolyte solute increases the boiling point of water by 0.104 K.


The boiling point to a solution containing 50 gm of a non-volatile solute in 1 kg of solvent is 0.5° higher than that of pure solvent. Determine the molecular mass of the solute (give molecular mass of solvent) = 78 g mol–1 and kb for solvent = 2.53 km–1)


Calculate the boiling point elevation for a solution prepared by adding 10 g of MgCl2 to 200 g of water, assuming MgCl2 is completely dissociated.

(Kb for Water = 0.512 K kg mol−1, Molar mass MgCl2 = 95 g mol−1)


Which of the following aqueous solutions will exhibit the highest boiling point?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×