Advertisements
Advertisements
प्रश्न
Atoms X and Y form bcc crystalline structure. Atom X is present at the corners of the cube and Y is at the centre of the cube. What is the formula of the compound?
Advertisements
उत्तर
Atoms X and Y form bcc crystalline structure. Atom X is present at the corners of the cube Atom Y is present at the centre of the cube.
No. of atoms of X in the unit cell = `"N"_"c"/8 = 8/8` = 1
No. of atoms of Y in the unit cell = `"N"_"b"/1 = 1/1` = 1
Ratio of atoms X : Y = 1 : 1
Hence formula of the compound = XY.
APPEARS IN
संबंधित प्रश्न
CsCl has bcc arrangement, its unit cell edge length is 400 pm, it's inter atomic distance is
The vacant space in bcc lattice unit cell is ____________.
The radius of an atom is 300 pm, if it crystallizes in a face centered cubic lattice, the length of the edge of the unit cell is ____________.
The fraction of total volume occupied by the atoms in a simple cubic is
If ‘a’ is the length of the side of the cube, the distance between the body-centered atom and one corner atom in the cube will be ______.
Potassium has a bcc structure with nearest neighbor distance 4.52 A0. its atomic weight is 39. its density will be
Explain briefly seven types of unit cells.
Calculate the number of atoms in a fcc unit cell.
Aluminium crystallizes in a cubic close packed structure. Its metallic radius is 125 pm. calculate the edge length of the unit cell.
Sodium metal crystallizes in bcc structure with the edge length of the unit cell 4.3 × 10−8 cm. calculate the radius of a sodium atom.
