Advertisements
Advertisements
प्रश्न
Atoms X and Y form bcc crystalline structure. Atom X is present at the corners of the cube and Y is at the centre of the cube. What is the formula of the compound?
Advertisements
उत्तर
Atoms X and Y form bcc crystalline structure. Atom X is present at the corners of the cube Atom Y is present at the centre of the cube.
No. of atoms of X in the unit cell = `"N"_"c"/8 = 8/8` = 1
No. of atoms of Y in the unit cell = `"N"_"b"/1 = 1/1` = 1
Ratio of atoms X : Y = 1 : 1
Hence formula of the compound = XY.
APPEARS IN
संबंधित प्रश्न
The number of unit cells in 8 gm of an element X (atomic mass 40) which crystallizes in bcc pattern is (NA is the Avogadro number)
CsCl has bcc arrangement, its unit cell edge length is 400 pm, it's inter atomic distance is
The vacant space in bcc lattice unit cell is ____________.
The fraction of total volume occupied by the atoms in a simple cubic is
If ‘a’ stands for the edge length of the cubic system; sc, bcc, and fcc. Then the ratio of radii of spheres in these systems will be respectively.
If ‘a’ is the length of the side of the cube, the distance between the body-centered atom and one corner atom in the cube will be ______.
Explain briefly seven types of unit cells.
What is the coordination number of atoms in a bcc structure?
Aluminium crystallizes in a cubic close packed structure. Its metallic radius is 125 pm. calculate the edge length of the unit cell.
Sodium metal crystallizes in bcc structure with the edge length of the unit cell 4.3 × 10−8 cm. calculate the radius of a sodium atom.
