Advertisements
Advertisements
प्रश्न
The fraction of total volume occupied by the atoms in a simple cubic is
विकल्प
`(π/(4sqrt2))`
`(π/6)`
`(π/4)`
`(π/(3sqrt2))`
Advertisements
उत्तर
`(π/6)`
APPEARS IN
संबंधित प्रश्न
CsCl has bcc arrangement, its unit cell edge length is 400 pm, it's inter atomic distance is
The vacant space in bcc lattice unit cell is ____________.
The radius of an atom is 300 pm, if it crystallizes in a face centered cubic lattice, the length of the edge of the unit cell is ____________.
If ‘a’ is the length of the side of the cube, the distance between the body-centered atom and one corner atom in the cube will be ______.
Explain briefly seven types of unit cells.
Calculate the number of atoms in a fcc unit cell.
What is meant by the term “coordination number”?
An element has bcc structure with a cell edge of 288 pm. The density of the element is 7.2 g cm−3. How many atoms are present in 208 g of the element?
KF crystallizes in fcc structure like sodium chloride. calculate the distance between K+ and F− in KF.
(Given: density of KF is 2.48 g cm−3)
An atom crystallizes in fcc crystal lattice and has a density of 10 g cm−3 with unit cell edge length of 100 pm. calculate the number of atoms present in 1 g of crystal.
