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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान कक्षा ११

At a Prayer Meeting, the Disciples Sing Jai-ram Jai-ram. the Sound Amplified by a Loudspeaker Comes Back After Reflection from a Building at a Distance of 80 M from the Meeting.

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प्रश्न

At a prayer meeting, the disciples sing JAI-RAM JAI-RAM. The sound amplified by a loudspeaker comes back after reflection from a building at a distance of 80 m from the meeting. What maximum time interval can be kept between one JAI-RAM and the next JAI-RAM so that the echo does not disturb a listener sitting in the meeting. Speed of sound in air is 320 m s−1.

योग
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उत्तर

Given:
The distance of the building from the meeting is 80 m.
Velocity of sound in air v = 320 ms−1
Total distance travelled by the sound after echo is S = 80 × 2 = 160 m
As we know, 

\[v = \frac{S}{t}\]

\[\therefore   t = \frac{s}{v} = \frac{160}{320} = 0 . 5 \text{ s }\]

Therefore, the maximum time interval will be 0.5 seconds.

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Speed of Wave Motion
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 16: Sound Waves - Exercise [पृष्ठ ३५३]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 16 Sound Waves
Exercise | Q 2 | पृष्ठ ३५३

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