हिंदी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान कक्षा ११

Two Submarines Are Approaching Each Other in a Calm Sea. the First Submarine Travels at a Speed of 36 Km H−1 and the Other at 54 Km H−1 Relative to the Water. - Physics

Advertisements
Advertisements

प्रश्न

Two submarines are approaching each other in a calm sea. The first submarine travels at a speed of 36 km h−1 and the other at 54 km h−1 relative to the water. The first submarine sends a sound signal (sound waves in water are also called sonar) at a frequency of 2000 Hz. (a) At what frequency is this signal received from the second submarine. At what frequency is this signal received by the first submarine. Take the speed of of the sound wave in water to be 1500 m s−1.

योग
Advertisements

उत्तर

Given:
Velocity of water v = 1500 m/s
Frequency of sound signal \[f_0\]= 2000 Hz
Velocity of first submarine vs = 36 kmh−1 = \[36 \times \frac{5}{18} \text{ m/s }\]

Velocity of second submarine \[v_0\]= 54 km h−1  = \[54 \times \frac{5}{18}\] m/s = 15 m/s
Frequency received by the first submarine \[\left( f_1 \right)\] is given by:

\[f_1    = \left( \frac{v  + v_0}{v  - v_s} \right) f_0\]

On substituting the values, we get:

\[f_1    = \left( \frac{1500 + 15}{1500 - 10} \right) \times (2000)\] 

\[         =   2034  \text { Hz }\]

(b) Here, 

\[f_0    =   2034  Hz\]

Apparent frequency received by second submarine \[\left( f_2 \right)\] is given by :

\[f_2    = \left( \frac{1500 + 10}{1500 - 15} \right) \times (2034)\] 

\[       = 2068  \text { Hz }\]

shaalaa.com
Speed of Wave Motion
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 16: Sound Waves - Exercise [पृष्ठ ३५७]

APPEARS IN

एचसी वर्मा Concepts of Physics Vol. 1 [English] Class 11 and 12
अध्याय 16 Sound Waves
Exercise | Q 76 | पृष्ठ ३५७

संबंधित प्रश्न

Two waves represented by \[y = a\sin\left( \omega t - kx \right)\] and \[y = a\cos\left( \omega t - kx \right)\] \[y = a\cos\left( \omega t - kx \right)\] are superposed. The resultant wave will have an amplitude 


Two periodic waves of amplitudes A1 and A2 pass thorough a region. If A1 > A2, the difference in the maximum and minimum resultant amplitude possible is


following Figure shows a wave pulse at t = 0. The pulse moves to the right with a speed of 10 cm s−1. Sketch the shape of the string at t = 1 s, 2 s and 3 s.


Two particles A and B have a phase difference of π when a sine wave passes through the region.
(a) A oscillates at half the frequency of B.
(b) A and B move in opposite directions.
(c) A and B must be separated by half of the wavelength.
(d) The displacements at A and B have equal magnitudes.


The speed of sound in a medium depends on


Calculate the speed of sound in oxygen from the following data. The mass of 22.4 litre of oxygen at STP (T = 273 K and p = 1.0 × 105 N m−2) is 32 g, the molar heat capacity of oxygen at constant volume is Cv = 2.5 R and that at constant pressure is Cp = 3.5 R.


Two stereo speakers are separated by a distance of 2.40 m. A person stands at a distance of 3.20 m directly in front of one of the speakers as shown in figure. Find the frequencies in the audible range (20-2000 Hz) for which the listener will hear a minimum sound intensity. Speed of sound in air = 320 m s−1.


An open organ pipe has a length of 5 cm. (a) Find the fundamental frequency of vibration of this pipe. (b) What is the highest harmonic of such a tube that is in the audible range? Speed of sound in air is 340 m s−1 and the audible range is 20-20,000 Hz.


An electronically driven loudspeaker is placed near the open end of a resonance column apparatus. The length of air column in the tube is 80 cm. The frequency of the loudspeaker can be varied between 20 Hz and 2 kHz. Find the frequencies at which the column will resonate. Speed of sound in air = 320 m s−1.


Two successive resonance frequencies in an open organ pipe are 1944 Hz and 2592 Hz. Find the length of the tube. The speed of sound in air is 324 ms−1.


A U-tube having unequal arm-lengths has water in it. A tuning fork of frequency 440 Hz can set up the air in the shorter arm in its fundamental mode of vibration and the same tuning fork can set up the air in the longer arm in its first overtone vibration. Find the length of the air columns. Neglect any end effect and assume that the speed of sound in air = 330 m s−1.


A Kundt's tube apparatus has a steel rod of length 1.0 m clamped at the centre. It is vibrated in its fundamental mode at a frequency of 2600 Hz. The lycopodium powder dispersed in the tube collects into heaps separated by 6.5 cm. Calculate the speed of sound in steel and in air.


Two trains are travelling towards each other both at a speed of 90 km h−1. If one of the trains sounds a whistle at 500 Hz, what will be the apparent frequency heard in the other train? Speed of sound in air = 350 m s−1.


A car moving at 108 km h−1 finds another car in front it going in the same direction at 72 km h−1. The first car sounds a horn that has a dominant frequency of 800 Hz. What will be the apparent frequency heard by the driver in the front car? Speed of sound in air = 330 m s−1.


A wave of frequency 500 Hz is traveling with a speed of 350 m/s. (a) What is the phase difference between two displacements at a certain point at times 1.0 ms apart? (b) what will be the smallest distance between two points which are 45° out of phase at an instant of time?


The speed of sound in hydrogen is 1270 m/s. The speed of sound in the mixture of oxygen and hydrogen in which they are mixed in 1:4 ratio is


Change in temperature of the medium changes ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×