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A Copper Rod of Length 1.0 M is Clamped at Its Middle Point. Find the Frequencies Between 20 Hz and 20,000 Hz at Which Standing Longitudinal Waves Can Be Set up in the Rod.

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प्रश्न

A copper rod of length 1.0 m is clamped at its middle point. Find the frequencies between 20 Hz and 20,000 Hz at which standing longitudinal waves can be set up in the rod. The speed of sound in copper is 3.8 km s−1.

योग
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उत्तर

Given:
Length of copper rod l = 1.0 m
Speed of sound in copper v = 3.8 kms−1 = 3800 m/s
Let f be the frequency of the longitudinal waves.
Wavelength \[\left( \lambda \right)\] will be :

\[\frac{\lambda}{2} = I\] 

\[ \Rightarrow   \lambda = 2I = 2 \times 1 = 2  \text { m }\]

We know that:
v = fλ

\[\Rightarrow f = \frac{v}{\lambda}\]

So,

\[f = \frac{3800}{2} = 1 . 9  \text { KHz } \]

Therefore, the frequencies between 20 Hz and 20 kHz that will be heard are
= n × 1.9 kHz,
where n = 0, 1, 2, 3, ...10.

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अध्याय 16: Sound Waves - Exercise [पृष्ठ ३५५]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 16 Sound Waves
Exercise | Q 43 | पृष्ठ ३५५

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