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प्रश्न
Arrange the following.
In decreasing order of basic strength in gas phase (C2H5)NH2, (C2H5)NH, (C2H5)3N and NH3.
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उत्तर
In the gas phase, solvent effects i.e., stabilization of the conjugate acids due to H-bonding, are absent. Therefore, in the gas phase, basic strength mainly depends upon the +I effect of the alkyl groups. Since the +I effect increases with the number of alkyl groups, therefore the basic strength of the amines decreases as the number of ethyl groups decreases from three in (C2H5)3N to two in (C2H5)2NH to one in C2H5NH2 and zero in NH3.
Basic strength in the gas phase decreases in the order is, (C2H5)3N > (C2H5)NH2 > (C2H5)NH > NH3.
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संबंधित प्रश्न
Classify the following amine as primary, secondary or tertiary:
(C2H5)2NH
Choose the most correct option.
Which type of amine does produce N2 when treated with HNO2?
Choose the most correct option.
Identify ‘B’ in the following reactions
\[\ce{CH3 - C ≡ N ->[Na/C2H5OH] A ->[NaNO2/dilHCl]B}\]
What are amines?
IUPAC name for the amine is:
\[\begin{array}{cc}
\phantom{.}\ce{CH3}\\
|\phantom{..}\\
\ce{CH3 - N - C - CH2 - CH3}\\
\phantom{.}|\phantom{.....}|\phantom{........}\\
\phantom{}\ce{CH3}\phantom{..}\ce{C2H5}\phantom{....}
\end{array}\]
Write a short note on the following.
Schotten-Baumann reaction
Arrange the following.
Increasing order of basic strength C6H5NH2, C6H5N(CH3)2, (C2H5)2NH and CH3NH2.
How will you prepare propan-1-amine from butane nitrile?
How will you prepare propan-1-amine from 1-nitropropane?
Write a short note on the following.
Ammonolysis
