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Answer the following question. State Kepler’s law of period. - Physics

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प्रश्न

Answer the following question.

State Kepler’s law of the period.

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उत्तर

Statement:

The square of the time period of revolution of a planet around the Sun is proportional to the cube of the semimajor axis of the ellipse traced by the planet.

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अध्याय 5: Gravitation - Exercises [पृष्ठ ९७]

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बालभारती Physics [English] Standard 11 Maharashtra State Board
अध्याय 5 Gravitation
Exercises | Q 2. (ii) | पृष्ठ ९७

संबंधित प्रश्न

State Kepler's law of orbit and law of equal areas.


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A Saturn year is 29.5 times the earth year. How far is the Saturn from the sun if the earth is 1.50 ×108 km away from the sun?


State Kepler's laws of planetary motion.


Let the period of revolution of a planet at a distance R from a star be T. Prove that if it was at a distance of 2R from the star, its period of revolution will be \[\sqrt{8}\] T.


In the Following figure shows the elliptical path of a planet about the sun. The two shaded parts have equal area. If t1 and t2 be the time taken by the planet to go from a to b and from c to d respectively,


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Observe the given figure showing the orbit of a planet moving around the Sun and write the three laws related to it:


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Observe the given figure and answer these following questions.


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If the distance between the sun and the earth is made three times, then attraction between the two will ______


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The earth moves around the sun in an elliptical orbit as shown in the figure. The ratio, `"OA"/"OB"` = x. The ratio of the speed of the earth at Band at A is ______.


To verify Kepler's third law graphically four students plotted graphs. Student A plotted a graph of T (period of revolution of planets) versus r (average distance of planets from the sun) and found the plot is straight line with slope 1.85. Student B plotted a graph of T2 v/s r3 and found the plot is straight line with slope 1.39 and negative Y-intercept. Student C plotted graph of log T v/s log r and found the plot is straight line with slope 1.5. Student D plotted graph of log T v/s log r and found the plot is straight line with slope 0.67 and with negative X-intercept. The correct graph is of student


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