Advertisements
Advertisements
प्रश्न
An object falling freely from rest reaches ground in 2 s. If acceleration due to gravity is 9.8 m s-2, then the velocity of object on reaching the ground will be
विकल्प
9.8 m s-1
4.9 m s-1
19.6 m s-1
Zero
Advertisements
उत्तर
An object falling freely from rest reaches ground in 2 s. If acceleration due to gravity is 9.8 m s-2, then the velocity of object on reaching the ground will be 19.6 m s-1
METHOD: Given, u = 0
g = 9.8 m/s2
Time t = 2s
Let 'v' be the velocity of object on reaching the ground.
Using the first equation of motion,
v = u + gt
We get,
v = 0 + (9.8) (2)
Or, v = 19.6 m/s.
APPEARS IN
संबंधित प्रश्न
A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity just before touching the ground.
A stone is thrown vertically upward with an initial velocity of 40 m/s. Taking g = 10 m/s2, find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?
What is the usual value of the acceleration due to gravity of earth ?
Why does a sharp knife cut objects more effectively than a blunt knife ?
A force of 10 N acts on a body of mass 5 kg. Find the acceleration produced.
A force causes an acceleration of 10 m s-2 in a body of mass 500 g. What acceleration will be caused by the same force in a body of mass 5 kg?
A car is moving with a uniform velocity 30 ms-1. It is stopped in 2 s by applying a force of 1500 N through its brakes. Calculate the following values : The retardation produced in car.
How is the acccelaration due to gravity on the surface of the earth realted to its mass and radius ?
A body falls freely under gravity from rest and reaches the ground in time t. Write the expression for the height fallen by the body.
The value of gravitational acceleration at the centre of earth is zero.
