Advertisements
Advertisements
प्रश्न
Alcohols are comparatively more soluble in water than hydrocarbons of comparable molecular masses. Explain this fact.
Advertisements
उत्तर
Alcohols are more soluble in water compared to hydrocarbons with equivalent molecular weight because alcohol molecules form hydrogen bonds with water and can also break the existing hydrogen bonds between water molecules, while hydrocarbons are unable to do this.
APPEARS IN
संबंधित प्रश्न
Give reasons for the following : Phenol is more acidic than ethanol.
Give reasons for the following : Boiling point of ethanol is higher in comparison to methoxymethane.
Explain why propanol has higher boiling point than that of the hydrocarbon, butane?
Give simple chemical tests to distinguish between the following pairs of compounds :
Ethanol and phenol
Arrange the following compounds in the increasing order of their acid strength:
p-cresol, p-nitrophenol, phenol
Identify the chiral molecule in the following pair :
Isopropyl alcohol is obtained by reacting which of the following alkenes with concentrated H2SO4 followed by boiling with H2O?
The correct order of boiling points for primary (1°), secondary (2°) and tertiary alcohol (3°) is:
Alcohols of low molecular weight are _____________.
Which one of the following alcohols is least soluble in water?
Assertion: Boiling points of alcohols and ethers are high.
Reason: They can form intermolecular hydrogen-bonding.
Arrange the following in the increasing order of their property indicated:
ethanol, ethanoic acid, benzoic acid (boiling point)
Assertion (A): Alcohols react both as nucleophiles and electrophiles.
Reason (R): The bond between C–O is broken when alcohols react as nucleophiles.
Select the most appropriate answer from the options given below:
How are the following conversion carried out?
Methyl magnesium bromide →2-Methylpropan-2-ol.
What is esterifications? How is an ester obtained from alcohol or phenol?
How are the following conversions carried out?
Methyl magnesium bromide → 2 -Methylpropan-2-ol.
How are the following conversions carried out?
\[\ce{Methyl magnesium bromide -> 2-Methylpropan-2-ol}\]
How is the following conversions carried out?
\[\ce{Methyl magnesium bromide → 2-Methylpropan-2-ol}\].
