Advertisements
Advertisements
प्रश्न
ABCD is a square. AC and BD intersect at O. State the measure of ∠AOB.
Advertisements
उत्तर

Since, diagonals of square bisect each other at right angle
∴`∠`ADB = 90°
APPEARS IN
संबंधित प्रश्न
In Fig., below, ABCD is a parallelogram in which ∠A = 60°. If the bisectors of ∠A and ∠B meet at P, prove that AD = DP, PC = BC and DC = 2AD.

In a parallelogram ABCD, if `∠`B = 135°, determine the measures of its other angles .
In Fig. below, AB = AC and CP || BA and AP is the bisector of exterior ∠CAD of ΔABC.
Prove that (i) ∠PAC = ∠BCA (ii) ABCP is a parallelogram

In a parallelogram ABCD, if ∠D = 115°, then write the measure of ∠A.
In a parallelogram ABCD, if ∠A = (3x − 20)°, ∠B = (y + 15)°, ∠C = (x + 40)°, then find the values of xand y.
In a parallelogram ABCD, the bisector of ∠A also bisects BC at X. Find AB : AD.
ABCD is a parallelogram in which diagonal AC bisects ∠BAD. If ∠BAC = 35°, then ∠ABC =
P is the mid-point of side BC of a parallelogram ABCD such that ∠BAP = ∠DAP. If AD = 10 cm, then CD =
In the given figure, ∠A = 64°, ∠ABC = 58°. If BO and CO are the bisectors of ∠ABC and ∠ACB respectively of ΔABC, find x° and y°
ABCD is a square, diagonals AC and BD meet at O. The number of pairs of congruent triangles with vertex O are
