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प्रश्न
ABCD is a parallelogram and X is the mid-point of AB. If ar (AXCD) = 24 cm2, then ar (ABC) = 24 cm2.
विकल्प
True
False
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उत्तर
This statement is False.
Explanation:
Given in the question, ABCD is a parallelogram and X is the mid-point of AB.
So, area(ABCD) = area(AXCD) + area(ΔXBC) ...(i)
Now, diagonal AC of a parallelogram divides it into two triangles of equal area.
area(ABCD) = 2area(ΔABC) ...(ii)
Similarly, X is the mid-point of AB,
So, area(ΔCXB) = `1/2`area(ΔABC) ...(iii) [Median divides the triangle in two triangles of equal area]
2area(ΔABC) = `24 + 1/2` area(ΔABC) ...[By using equation (i), (ii) and (iii)]
Now, 2area(ΔABC) – `1/2`area(ΔABC) = 24
`3/2`area(ΔABC) = 24
Therefore, area(ΔABC) = `(2 xx 24)/3` = 16 cm2.
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संबंधित प्रश्न
In a triangle ABC, E is the mid-point of median AD. Show that ar (BED) = 1/4ar (ABC).
In the given figure, ABC and ABD are two triangles on the same base AB. If line-segment CD is bisected by AB at O, show that ar (ABC) = ar (ABD).

In the given figure, diagonals AC and BD of quadrilateral ABCD intersect at O such that OB = OD. If AB = CD, then show that:
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[Hint: From D and B, draw perpendiculars to AC.]

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