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ABCD is a trapezium with AB || DC. A line parallel to AC intersects AB at X and BC at Y. Prove that ar (ADX) = ar (ACY). - Mathematics

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प्रश्न

ABCD is a trapezium with AB || DC. A line parallel to AC intersects AB at X and BC at Y. Prove that ar (ADX) = ar (ACY). 

[Hint: Join CX.]

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उत्तर

It can be observed that ΔADX and ΔACX lie on the same base AX and are between the same parallels AB and DC.

∴ Area (ΔADX) = Area (ΔACX) ... (1)

ΔACY and ΔACX lie on the same base AC and are between the same parallels AC and XY.

∴ Area (ΔACY) = Area (ACX) ... (2)

From equations (1) and (2), we obtain

Area (ΔADX) = Area (ΔACY)

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अध्याय 9: Areas of Parallelograms and Triangles - Exercise 9.3 [पृष्ठ १६४]

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एनसीईआरटी Mathematics [English] Class 9
अध्याय 9 Areas of Parallelograms and Triangles
Exercise 9.3 | Q 13 | पृष्ठ १६४

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

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(i) ar (DOC) = ar (AOB)

(ii) ar (DCB) = ar (ACB)

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[Hint: From D and B, draw perpendiculars to AC.]


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(iv) ar (BFE) = ar (AFD)

(v) ar (BFE) = 2 ar (FED)

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