हिंदी

A work of 1000 J is done on a body in 4 s, such that a displacement of 20 m is caused. Calculate (a) Force (b) Power.

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प्रश्न

A work of 1000 J is done on a body in 4 s, such that a displacement of 20 m is caused. Calculate

  1. Force
  2. Power
संख्यात्मक
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उत्तर

Given: Work (W) = 1000 J

Displacement (s) = 20 m

Time (t) = 4 s

(a) Work = Force × Displacement

1000 J = Force × 20 m

∴ Force = \[\frac{1000}{20}\]

= 50 N

(b) \[ \text{Power} = \frac{\text{Work}}{\text{Time}} \]

= \[\frac{1000\ \mathrm{J}}{4\ \mathrm{s}} \]

= 250 W

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अध्याय 2: Work, Power and Energy - NUMERICAL PROBLEMS ON WORK, POWER AND ENERGY [पृष्ठ ३६]

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गोयल ब्रदर्स प्रकाशन A New Approach to ICSE Physics [English] Class 10
अध्याय 2 Work, Power and Energy
NUMERICAL PROBLEMS ON WORK, POWER AND ENERGY | Q 1. | पृष्ठ ३६
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