Advertisements
Advertisements
प्रश्न
A triangle and a parallelogram have the same base and the same area. If the sides of triangle are 26 cm, 28 cm and 30 cm, and the parallelogram stands on the base 28 cm, find the height of the parallelogram.
Advertisements
उत्तर
For triangle
Perimeter of triangle = (26 + 28 + 30) cm = 84 cm
2s = 84 cm
s = 42 cm
By Heron’s formula,
`"Area of triangle "=sqrt(s(s-a)(s-b)(s-c))`
`"Area of triangle "=[sqrt(42(42-26)(42-28)(42-30))]cm^2`
`=[sqrt(42(16)(14)(12))]cm^2`
= 336 cm2
Let the height of the parallelogram be h.
Area of parallelogram = Area of triangle
h × 28 cm = 336 cm2
h = 12 cm
Therefore, the height of the parallelogram is 12 cm.
संबंधित प्रश्न
A rhombus shaped field has green grass for 18 cows to graze. If each side of the rhombus is 30 m and its longer diagonal is 48 m, how much area of grass field will each cow be getting?
The perimeter of a triangullar field is 144 m and the ratio of the sides is 3 : 4 : 5. Find the area of the field.
Find the area of an equilateral triangle having altitude h cm.
The base of an isosceles right triangle is 30 cm. Its area is
The sides of a triangular field are 325 m, 300 m and 125 m. Its area is
Find the area of a quadrilateral ABCD whose sides are AB = 13 cm, BC = 12 cm, CD = 9 cm, AD = 14 cm and diagonal BD = 15 cm
A park is in the shape of a quadrilateral. The sides of the park are 15 m, 20 m, 26 m and 17 m and the angle between the first two sides is a right angle. Find the area of the park
If the area of an equilateral triangle is `16sqrt(3)` cm2, then the perimeter of the triangle is ______.
The area of the equilateral triangle is `20sqrt(3)` cm2 whose each side is 8 cm.
