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A student records the initial length l, change in temperature ∆T and change in length ∆l of a rod as follows:

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प्रश्न

A student records the initial length l, change in temperature ∆T and change in length ∆l of a rod as follows:

S.No. l(m) ∆T (C) ∆l (m)
1. 2 10 `4 xx 10^-4`
2. 1 10 `4 xx 10^-4`
3. 2 20 `2 xx 10^-4`
4. 3 10 `6 xx 10^-4`

If the first observation is correct, what can you say about observations 2, 3 and 4.

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उत्तर

As per the 1st observation, we can infer that linear expansion α is,

α = `(∆l)/(l∆t)`

= `(4 xx 10^-4)/(2 xx 10)`

= `2 xx 10^(-5^circ) C^-1`

For observation no. 2, 

α = `(∆l)/(l∆t)`

`∆l = αl∆t`

= `2 xx 10^-5 xx 1 xx 10`

= `2 xx 10^-4 m`

But given value is `∆l = 4 xx 10^-4  m`

So, 2nd observation is incorrect.

For observation no. 3, 

α = `(∆l)/(l∆t)`

`∆l = αl∆t`

= `2 xx 10^-5 xx 2 xx 20`

= `8 xx 10^-4  m`

But the given value is `∆l = 2 xx 10^-4  m`

So, 3rd observation is incorrect.

For observation no. 4, 

α = `(∆l)/(l∆t)`

`∆l = αl∆t`

= `2 xx 10^-5 xx 3 xx 10`

= `6 xx 10^-4  m`

 Here the obtained value is the same as the given value.

So, the 4th observation is correct.

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अध्याय 11: Thermal Properties of Matter - Exercises [पृष्ठ ८०]

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एनसीईआरटी एक्झांप्लर Physics Exemplar [English] Class 11
अध्याय 11 Thermal Properties of Matter
Exercises | Q 11.14 | पृष्ठ ८०

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